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is_feed() - 判断该查询是否用于feed - WordPress函数 - WordPress动力
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is_feed( string|string[] $feeds = '' )

判断该查询是否用于feed


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feed

is 条件判断more...


描述

更多类似的主题函数信息,请查看主题开发手册中的条件标签文章。


参数

$feeds

(string|string[]) (可选) 要检查的feed类型或feed类型数组。

默认值: ''


返回

(bool) 该查询是否用于feed。



源码

查看源码 官方文档


更新日志

版本描述
1.5.0开始引入

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